(1/4)^3z-1=16^z+2*64^z-2

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Solution for (1/4)^3z-1=16^z+2*64^z-2 equation: 



(1/4)^3z-1=16^z+2*64^z-2

We move all terms to the left:

(1/4)^3z-1-(16^z+2*64^z-2)=0



Domain of the equation: 4)^3z!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+1/4)^3z-(16^z+2*64^z-2)-1=0

We get rid of parentheses

(+1/4)^3z-16^z-2*64^z+2-1=0

We multiply all the terms by the denominator


(+1-16^z*4)^3z-(2*64^z)*4)^3z+2*4)^3z-1*4)^3z=0

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